# Line slope calculator x-8y=-6

**Straight line given by points A[2; 1] and B[10; 2]**

## Calculation:

**Slope-intercept form of line:**y = 0.125x+0.75

**Canonical form of the line equation:**x-8y+6 = 0

**Parametric form of the line equation:**

x = 8t+2

y = t+1 ; t ∈ R

**Slope:**m = 0.125

**Slope angle of line: φ =**7°7'30″ = 0.1244 rad

**X intercept:**x

_{0}= -6

**Y intercept:**y

_{0}= q = 0.75

**Distance line from the origin:**d

_{0}= 0.7442

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; 1)

**Normal vector: n =**(1; -8)

**Midpoint of the segment AB: M =**[6; 1.5]

**Perpendicular Bisector equation:**8x+y-49.5 = 0

**Vector OA = (2; 1) ; |OA| = 2.2361**

**Vector OB = (10; 2) ; |OB| = 10.198**

**Scalar product OA .OB = 22**

**Angle ∠ AOB = 15°15'18″ = 0.2663 rad**